2x^2-19x+17=0

Solution for 2x^2-19x+17=0 equation:

Simplifying
2x2 + -19x + 17 = 0

Reorder the terms:
17 + -19x + 2x2 = 0

Solving
17 + -19x + 2x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(1 + -1x)(17 + -2x) = 0

Subproblem 1
Set the factor '(1 + -1x)' equal to zero and attempt to solve:

Simplifying
1 + -1x = 0

Solving
1 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1x = 0 + -1
-1x = 0 + -1

Combine like terms: 0 + -1 = -1
-1x = -1

Divide each side by '-1'.
x = 1

Simplifying
x = 1
Subproblem 2
Set the factor '(17 + -2x)' equal to zero and attempt to solve:

Simplifying
17 + -2x = 0

Solving
17 + -2x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-17' to each side of the equation.
17 + -17 + -2x = 0 + -17

Combine like terms: 17 + -17 = 0
0 + -2x = 0 + -17
-2x = 0 + -17

Combine like terms: 0 + -17 = -17
-2x = -17

Divide each side by '-2'.
x = 8.5

Simplifying
x = 8.5
Solution
x = {1, 8.5}